Any and All Operator In Python

Any operator

This operator return True if any of the items in the list is True. It return False if empty or all the items are False.

Example #1:-

print(any([False,False, False]))

Python

Output :-

False

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Example #2:-

print(any([False, True, False]))

Python

Output :-

True

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Example #3 :- Program using any operator

list1 = []
list2 = []
 
for i in range(10):
    list1.append(4*i)
     
for i in range(10):
    c = list1[i] % 5 == 0
    list2.append(c)
 
print(list2)
print(any(list2))

Python

Output :-

[True, False, False, False, False, True, False, False, False, False]  
                                                                        
True

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Explanation :- Its return True because in the list its find one item is True

All operator

This all operator return True if all the items of the list are True, if any one of them is False then it will return False.

Example #4:-

print(all([True, True, True]))
 
print(all([True, False, True]))

Python

Output :-

True
False

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 Example #5 :-

list1 = []
list2 = []
 
for i in range(21):
    list1.append(4*i-3)
     
for i in range(20):
    c = list1[i] % 2 == 1
    list2.append(c)
 
print(list2)
 
print(any(list2))

Python

 Output :-

[True, True, True, True, True, True, True, True, True, True, True, True, True, True, True, True, True, True, True, True]
                      
True

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 Explanation :- Its return True because all the items in the list are True.

I hope You understand the concept of the Any and All operator in python. If you have any query or suggestion please do a comment.

Thank You.